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Topic Products and Algorithms / Satellite Data Products & Algorithms / Rayleigh corrected reflectance (locked)
Has anyone derived MODIS rayleigh corrected reflectance using Seadas. It was suggested I use MODIS values of Lt - Lr to obtain a rayleigh corrected radiance, and then convert that to reflectance. Does that sound feasible?
Any advice gratefully received.
regards
Will
Any advice gratefully received.
regards
Will
Use rhos.
MSl12 has an output product, rhos_nnn (where nnn is wavelength - e.g. rhos_412)
This product is TOA reflectance minus Rayleigh reflectance.
Sean
MSl12 has an output product, rhos_nnn (where nnn is wavelength - e.g. rhos_412)
This product is TOA reflectance minus Rayleigh reflectance.
Sean
Hi Sean, thanks for that. I did get some seadas feedback previously about rhos_nnn ..........."There is no product that is simply Rayleigh-corrected reflectance.
The rhos product is quasi-surface reflectance (surface + aerosol)."
So I wasn't sure if it was atmospherically corrected or not. That was why I was initially deriving Lt-Lr.
Can you clarify, thanks
regards
Will
The rhos product is quasi-surface reflectance (surface + aerosol)."
So I wasn't sure if it was atmospherically corrected or not. That was why I was initially deriving Lt-Lr.
Can you clarify, thanks
regards
Will
Will,
What do you mean by 'atmospherically corrected'?
Removing Rayleigh is a partial atmospheric correction, so in that
sense Lt-Lr is 'partially' atmospherically corrected.
As for rhos, it does not remove aerosol reflectance, but does make
adjustments for various atmospheric transmittances, hence the
seadas group's remark that it is a quasi-surface reflectance.
Here's what it is :
rhos = PI / F0 / mu0 * (Lt / tg_sol / tg_sen - Lr) / t_sol / t_sen / t_o2 / t_h2o
(the t's are the various transmittances, mu0 is cosine solar zenith, F0 is extraterrestiral irradiance)
If you want a product that is simply total reflectance minus rayleigh reflectance, you'll need to
make your own ala:
rhot-r = PI / F0 / mu0 * (Lt - Lr)
Sean
What do you mean by 'atmospherically corrected'?
Removing Rayleigh is a partial atmospheric correction, so in that
sense Lt-Lr is 'partially' atmospherically corrected.
As for rhos, it does not remove aerosol reflectance, but does make
adjustments for various atmospheric transmittances, hence the
seadas group's remark that it is a quasi-surface reflectance.
Here's what it is :
rhos = PI / F0 / mu0 * (Lt / tg_sol / tg_sen - Lr) / t_sol / t_sen / t_o2 / t_h2o
(the t's are the various transmittances, mu0 is cosine solar zenith, F0 is extraterrestiral irradiance)
If you want a product that is simply total reflectance minus rayleigh reflectance, you'll need to
make your own ala:
rhot-r = PI / F0 / mu0 * (Lt - Lr)
Sean
Topic Products and Algorithms / Satellite Data Products & Algorithms / Rayleigh corrected reflectance (locked)
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